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Taking Maths Further Podcast
Peter Rowlett and Katie Steckles
20 episodes
3 months ago
Talking to people who use maths in their work. Aiming to encourage further uptake of maths at A-level and beyond. brought to you by the Further Maths Support Programme. The FMSP supports students and teachers in England with mathematics, and you can find out more at furthermaths.org.uk. Hosts: Peter Rowlett (Nottingham Trent University) and Katie Steckles.
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Education
Natural Sciences
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All content for Taking Maths Further Podcast is the property of Peter Rowlett and Katie Steckles and is served directly from their servers with no modification, redirects, or rehosting. The podcast is not affiliated with or endorsed by Podjoint in any way.
Talking to people who use maths in their work. Aiming to encourage further uptake of maths at A-level and beyond. brought to you by the Further Maths Support Programme. The FMSP supports students and teachers in England with mathematics, and you can find out more at furthermaths.org.uk. Hosts: Peter Rowlett (Nottingham Trent University) and Katie Steckles.
Show more...
Education
Natural Sciences
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Episode 4: Nautical Radar and quadratic equations
Taking Maths Further Podcast
11 years ago
Episode 4: Nautical Radar and quadratic equations
This week the topic was quadratic equations and their applications. We interviewed Colin Wright, who works on radar systems for coordinating and tracking ships and boats. Interesting links: Quadratic equations in the real world Marine Radar on Wikipedia How to use the quadratic formula Path of a projectile (interactive GeoGebra page) Puzzle: A boat is going to sail 20km upstream along a river, then 20km back to where it started. Due to the speed of water flowing in the river, its speed is reduced by 2kph on the way upstream and increased by 2kph on the way downstream. If the speed of the boat’s engine is x (kph), this means it travels 20km at (x-2)kph and then 20km at (x+2)kph. The total journey needs to take 3.5 hours. What value of x does the boat driver need to use? Solution: Since speed = distance / time we can rearrange that to get time = distance / speed. Then our speed is (x-2) on the way out and (x+2) on the way back, so 20/(x-2) + 20/(x+2) = 3.5 Multiply through by (x+2) and (x-2): 20(x+2) + 20(x-2) = 3.5(x+2)(x-2) Now expand the brackets to get a quadratic equation: 3.5x^2 - 40x - 14 = 0. We can use the quadratic formula to get two solutions (one positive and one negative), but we know that x is positive, as it’s a speed so x=11.77kph. Show/Hide
Taking Maths Further Podcast
Talking to people who use maths in their work. Aiming to encourage further uptake of maths at A-level and beyond. brought to you by the Further Maths Support Programme. The FMSP supports students and teachers in England with mathematics, and you can find out more at furthermaths.org.uk. Hosts: Peter Rowlett (Nottingham Trent University) and Katie Steckles.