Home
Categories
EXPLORE
True Crime
Comedy
Society & Culture
Business
Sports
Technology
Health & Fitness
About Us
Contact Us
Copyright
© 2024 PodJoint
Podjoint Logo
US
00:00 / 00:00
Sign in

or

Don't have an account?
Sign up
Forgot password
https://is1-ssl.mzstatic.com/image/thumb/Podcasts124/v4/bd/c8/88/bdc888b0-c1c3-458a-8a8a-b2023891dc3e/mza_4230201374763518694.jpg/600x600bb.jpg
cpp.chat
Jon Kalb & Phil Nash
59 episodes
9 months ago
Each fortnight, or thereabouts, we chat with guests from the C++ community about what they're doing, what interests them, and what's going on in the world of C++
Show more...
Tech News
Technology,
News
RSS
All content for cpp.chat is the property of Jon Kalb & Phil Nash and is served directly from their servers with no modification, redirects, or rehosting. The podcast is not affiliated with or endorsed by Podjoint in any way.
Each fortnight, or thereabouts, we chat with guests from the C++ community about what they're doing, what interests them, and what's going on in the world of C++
Show more...
Tech News
Technology,
News
https://cpp.chat/assets/cover_medium.jpg
Izzy's 'Fine' With Modules
cpp.chat
1 hour 9 minutes 47 seconds
4 years ago
Izzy's 'Fine' With Modules

This week we chat with Isabella (Izzy) Muerte about modules, build systems and more. We talk about xyr new job (which, at the time of recording, was with Netlify), and how that still involves working on build systems - but particularly CMake, where xe has found an intriguing special use for emoji!

We segue into a discussion about modules, which Izzy was definitely down on a couple of years ago, and what xe thinks of them now. To avoid spoilers don’t read the title!

Links:

  • Izzy's (2017) rant on Modules
  • 'tag_invoke' - An Actually Good Way to Do Customization Points- Gašper Ažman's talk at C++ London
  • byteswap- P1272 - Byteswapping for fun&&nuf
  • retain_ptr- P0468 - An Intrusive Smart Pointer
  • Lambda Expressions on cppreference- constexpr: explicitly specifies that the function call operator is a constexpr function. When this specifier is not present, the function call operator will be constexpr anyway, if it happens to satisfy all constexpr function requirements (since C++17)
cpp.chat
Each fortnight, or thereabouts, we chat with guests from the C++ community about what they're doing, what interests them, and what's going on in the world of C++